3.18.98 \(\int \frac {(1-2 x)^{5/2} (3+5 x)}{(2+3 x)^3} \, dx\)

Optimal. Leaf size=96 \[ \frac {(1-2 x)^{7/2}}{42 (3 x+2)^2}-\frac {73 (1-2 x)^{5/2}}{126 (3 x+2)}-\frac {365}{567} (1-2 x)^{3/2}-\frac {365}{81} \sqrt {1-2 x}+\frac {365}{81} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ) \]

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Rubi [A]  time = 0.02, antiderivative size = 96, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {78, 47, 50, 63, 206} \begin {gather*} \frac {(1-2 x)^{7/2}}{42 (3 x+2)^2}-\frac {73 (1-2 x)^{5/2}}{126 (3 x+2)}-\frac {365}{567} (1-2 x)^{3/2}-\frac {365}{81} \sqrt {1-2 x}+\frac {365}{81} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((1 - 2*x)^(5/2)*(3 + 5*x))/(2 + 3*x)^3,x]

[Out]

(-365*Sqrt[1 - 2*x])/81 - (365*(1 - 2*x)^(3/2))/567 + (1 - 2*x)^(7/2)/(42*(2 + 3*x)^2) - (73*(1 - 2*x)^(5/2))/
(126*(2 + 3*x)) + (365*Sqrt[7/3]*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/81

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + 1)), x] - Dist[(d*n)/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {(1-2 x)^{5/2} (3+5 x)}{(2+3 x)^3} \, dx &=\frac {(1-2 x)^{7/2}}{42 (2+3 x)^2}+\frac {73}{42} \int \frac {(1-2 x)^{5/2}}{(2+3 x)^2} \, dx\\ &=\frac {(1-2 x)^{7/2}}{42 (2+3 x)^2}-\frac {73 (1-2 x)^{5/2}}{126 (2+3 x)}-\frac {365}{126} \int \frac {(1-2 x)^{3/2}}{2+3 x} \, dx\\ &=-\frac {365}{567} (1-2 x)^{3/2}+\frac {(1-2 x)^{7/2}}{42 (2+3 x)^2}-\frac {73 (1-2 x)^{5/2}}{126 (2+3 x)}-\frac {365}{54} \int \frac {\sqrt {1-2 x}}{2+3 x} \, dx\\ &=-\frac {365}{81} \sqrt {1-2 x}-\frac {365}{567} (1-2 x)^{3/2}+\frac {(1-2 x)^{7/2}}{42 (2+3 x)^2}-\frac {73 (1-2 x)^{5/2}}{126 (2+3 x)}-\frac {2555}{162} \int \frac {1}{\sqrt {1-2 x} (2+3 x)} \, dx\\ &=-\frac {365}{81} \sqrt {1-2 x}-\frac {365}{567} (1-2 x)^{3/2}+\frac {(1-2 x)^{7/2}}{42 (2+3 x)^2}-\frac {73 (1-2 x)^{5/2}}{126 (2+3 x)}+\frac {2555}{162} \operatorname {Subst}\left (\int \frac {1}{\frac {7}{2}-\frac {3 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )\\ &=-\frac {365}{81} \sqrt {1-2 x}-\frac {365}{567} (1-2 x)^{3/2}+\frac {(1-2 x)^{7/2}}{42 (2+3 x)^2}-\frac {73 (1-2 x)^{5/2}}{126 (2+3 x)}+\frac {365}{81} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )\\ \end {align*}

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Mathematica [C]  time = 0.03, size = 48, normalized size = 0.50 \begin {gather*} \frac {(1-2 x)^{7/2} \left (343-292 (3 x+2)^2 \, _2F_1\left (2,\frac {7}{2};\frac {9}{2};\frac {3}{7}-\frac {6 x}{7}\right )\right )}{14406 (3 x+2)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((1 - 2*x)^(5/2)*(3 + 5*x))/(2 + 3*x)^3,x]

[Out]

((1 - 2*x)^(7/2)*(343 - 292*(2 + 3*x)^2*Hypergeometric2F1[2, 7/2, 9/2, 3/7 - (6*x)/7]))/(14406*(2 + 3*x)^2)

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IntegrateAlgebraic [A]  time = 0.18, size = 81, normalized size = 0.84 \begin {gather*} \frac {365}{81} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )-\frac {\left (180 (1-2 x)^3+1752 (1-2 x)^2-12775 (1-2 x)+17885\right ) \sqrt {1-2 x}}{81 (3 (1-2 x)-7)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((1 - 2*x)^(5/2)*(3 + 5*x))/(2 + 3*x)^3,x]

[Out]

-1/81*((17885 - 12775*(1 - 2*x) + 1752*(1 - 2*x)^2 + 180*(1 - 2*x)^3)*Sqrt[1 - 2*x])/(-7 + 3*(1 - 2*x))^2 + (3
65*Sqrt[7/3]*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/81

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fricas [A]  time = 1.63, size = 86, normalized size = 0.90 \begin {gather*} \frac {365 \, \sqrt {7} \sqrt {3} {\left (9 \, x^{2} + 12 \, x + 4\right )} \log \left (-\frac {\sqrt {7} \sqrt {3} \sqrt {-2 \, x + 1} - 3 \, x + 5}{3 \, x + 2}\right ) + 3 \, {\left (720 \, x^{3} - 4584 \, x^{2} - 8731 \, x - 3521\right )} \sqrt {-2 \, x + 1}}{486 \, {\left (9 \, x^{2} + 12 \, x + 4\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)/(2+3*x)^3,x, algorithm="fricas")

[Out]

1/486*(365*sqrt(7)*sqrt(3)*(9*x^2 + 12*x + 4)*log(-(sqrt(7)*sqrt(3)*sqrt(-2*x + 1) - 3*x + 5)/(3*x + 2)) + 3*(
720*x^3 - 4584*x^2 - 8731*x - 3521)*sqrt(-2*x + 1))/(9*x^2 + 12*x + 4)

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giac [A]  time = 1.11, size = 86, normalized size = 0.90 \begin {gather*} -\frac {20}{81} \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - \frac {365}{486} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) - \frac {32}{9} \, \sqrt {-2 \, x + 1} + \frac {7 \, {\left (237 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 539 \, \sqrt {-2 \, x + 1}\right )}}{324 \, {\left (3 \, x + 2\right )}^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)/(2+3*x)^3,x, algorithm="giac")

[Out]

-20/81*(-2*x + 1)^(3/2) - 365/486*sqrt(21)*log(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x
+ 1))) - 32/9*sqrt(-2*x + 1) + 7/324*(237*(-2*x + 1)^(3/2) - 539*sqrt(-2*x + 1))/(3*x + 2)^2

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maple [A]  time = 0.01, size = 66, normalized size = 0.69 \begin {gather*} \frac {365 \sqrt {21}\, \arctanh \left (\frac {\sqrt {21}\, \sqrt {-2 x +1}}{7}\right )}{243}-\frac {20 \left (-2 x +1\right )^{\frac {3}{2}}}{81}-\frac {32 \sqrt {-2 x +1}}{9}-\frac {28 \left (-\frac {79 \left (-2 x +1\right )^{\frac {3}{2}}}{36}+\frac {539 \sqrt {-2 x +1}}{108}\right )}{3 \left (-6 x -4\right )^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-2*x+1)^(5/2)*(5*x+3)/(3*x+2)^3,x)

[Out]

-20/81*(-2*x+1)^(3/2)-32/9*(-2*x+1)^(1/2)-28/3*(-79/36*(-2*x+1)^(3/2)+539/108*(-2*x+1)^(1/2))/(-6*x-4)^2+365/2
43*arctanh(1/7*21^(1/2)*(-2*x+1)^(1/2))*21^(1/2)

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maxima [A]  time = 1.38, size = 92, normalized size = 0.96 \begin {gather*} -\frac {20}{81} \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - \frac {365}{486} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) - \frac {32}{9} \, \sqrt {-2 \, x + 1} + \frac {7 \, {\left (237 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 539 \, \sqrt {-2 \, x + 1}\right )}}{81 \, {\left (9 \, {\left (2 \, x - 1\right )}^{2} + 84 \, x + 7\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)/(2+3*x)^3,x, algorithm="maxima")

[Out]

-20/81*(-2*x + 1)^(3/2) - 365/486*sqrt(21)*log(-(sqrt(21) - 3*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) -
32/9*sqrt(-2*x + 1) + 7/81*(237*(-2*x + 1)^(3/2) - 539*sqrt(-2*x + 1))/(9*(2*x - 1)^2 + 84*x + 7)

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mupad [B]  time = 1.21, size = 74, normalized size = 0.77 \begin {gather*} -\frac {32\,\sqrt {1-2\,x}}{9}-\frac {20\,{\left (1-2\,x\right )}^{3/2}}{81}-\frac {\frac {3773\,\sqrt {1-2\,x}}{729}-\frac {553\,{\left (1-2\,x\right )}^{3/2}}{243}}{\frac {28\,x}{3}+{\left (2\,x-1\right )}^2+\frac {7}{9}}-\frac {\sqrt {21}\,\mathrm {atan}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}\,1{}\mathrm {i}}{7}\right )\,365{}\mathrm {i}}{243} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((1 - 2*x)^(5/2)*(5*x + 3))/(3*x + 2)^3,x)

[Out]

- (21^(1/2)*atan((21^(1/2)*(1 - 2*x)^(1/2)*1i)/7)*365i)/243 - (32*(1 - 2*x)^(1/2))/9 - (20*(1 - 2*x)^(3/2))/81
- ((3773*(1 - 2*x)^(1/2))/729 - (553*(1 - 2*x)^(3/2))/243)/((28*x)/3 + (2*x - 1)^2 + 7/9)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(5/2)*(3+5*x)/(2+3*x)**3,x)

[Out]

Timed out

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